3x-8/5x+8=1

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Solution for 3x-8/5x+8=1 equation:



3x-8/5x+8=1
We move all terms to the left:
3x-8/5x+8-(1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
We add all the numbers together, and all the variables
3x-8/5x+7=0
We multiply all the terms by the denominator
3x*5x+7*5x-8=0
Wy multiply elements
15x^2+35x-8=0
a = 15; b = 35; c = -8;
Δ = b2-4ac
Δ = 352-4·15·(-8)
Δ = 1705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1705}}{2*15}=\frac{-35-\sqrt{1705}}{30} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1705}}{2*15}=\frac{-35+\sqrt{1705}}{30} $

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