3(x+2)=7(2x+3)

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Solution for 3(x+2)=7(2x+3) equation: 



3(x+2)=7(2x+3)

We move all terms to the left:

3(x+2)-(7(2x+3))=0

We multiply parentheses

3x-(7(2x+3))+6=0



We calculate terms in parentheses: -(7(2x+3)), so:

7(2x+3)

We multiply parentheses

14x+21

Back to the equation:

-(14x+21)



We get rid of parentheses

3x-14x-21+6=0

We add all the numbers together, and all the variables

-11x-15=0

We move all terms containing x to the left, all other terms to the right

-11x=15

x=15/-11

x=-1+4/11

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