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(12+25)+(3x-10)=90
We move all terms to the left:
(12+25)+(3x-10)-(90)=0
determiningTheFunctionDomain (3x-10)-90+(12+25)=0
We add all the numbers together, and all the variables
(3x-10)-90+37=0
We add all the numbers together, and all the variables
(3x-10)-53=0
We get rid of parentheses
3x-10-53=0
We add all the numbers together, and all the variables
3x-63=0
We move all terms containing x to the left, all other terms to the right
3x=63
x=63/3
x=21
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