3(x+2)=4+3(x+1)

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Solution for 3(x+2)=4+3(x+1) equation: 



3(x+2)=4+3(x+1)

We move all terms to the left:

3(x+2)-(4+3(x+1))=0

We multiply parentheses

3x-(4+3(x+1))+6=0



We calculate terms in parentheses: -(4+3(x+1)), so:

4+3(x+1)

determiningTheFunctionDomain
3(x+1)+4

We multiply parentheses

3x+3+4

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We get rid of parentheses

3x-3x-7+6=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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