3(x+2)=2(x-1)-x-4

Solution for 3(x+2)=2(x-1)-x-4 equation:

3(x+2)=2(x-1)-x-4

We move all terms to the left:

3(x+2)-(2(x-1)-x-4)=0

We multiply parentheses

3x-(2(x-1)-x-4)+6=0


We calculate terms in parentheses: -(2(x-1)-x-4), so:

2(x-1)-x-4

We add all the numbers together, and all the variables

-1x+2(x-1)-4

We multiply parentheses

-1x+2x-2-4

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)


We get rid of parentheses

3x-x+6+6=0

We add all the numbers together, and all the variables

2x+12=0

We move all terms containing x to the left, all other terms to the right

2x=-12

x=-12/2

x=-6