3(x+2)=3(x-4)+2(x+5)

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Solution for 3(x+2)=3(x-4)+2(x+5) equation: 



3(x+2)=3(x-4)+2(x+5)

We move all terms to the left:

3(x+2)-(3(x-4)+2(x+5))=0

We multiply parentheses

3x-(3(x-4)+2(x+5))+6=0



We calculate terms in parentheses: -(3(x-4)+2(x+5)), so:

3(x-4)+2(x+5)

We multiply parentheses

3x+2x-12+10

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)



We get rid of parentheses

3x-5x+2+6=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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