3+r=6(4-r)

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Solution for 3+r=6(4-r) equation: 



3+r=6(4-r)

We move all terms to the left:

3+r-(6(4-r))=0

We add all the numbers together, and all the variables

r-(6(-1r+4))+3=0



We calculate terms in parentheses: -(6(-1r+4)), so:

6(-1r+4)

We multiply parentheses

-6r+24

Back to the equation:

-(-6r+24)



We get rid of parentheses

r+6r-24+3=0

We add all the numbers together, and all the variables

7r-21=0

We move all terms containing r to the left, all other terms to the right

7r=21

r=21/7

r=3

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