3(x+2)=2(x+1)+x+4

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Solution for 3(x+2)=2(x+1)+x+4 equation: 



3(x+2)=2(x+1)+x+4

We move all terms to the left:

3(x+2)-(2(x+1)+x+4)=0

We multiply parentheses

3x-(2(x+1)+x+4)+6=0



We calculate terms in parentheses: -(2(x+1)+x+4), so:

2(x+1)+x+4

We add all the numbers together, and all the variables

x+2(x+1)+4

We multiply parentheses

x+2x+2+4

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

3x-3x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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