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3(x+2)=2(2x+3)=-x
We move all terms to the left:
3(x+2)-(2(2x+3))=0
We multiply parentheses
3x-(2(2x+3))+6=0
We calculate terms in parentheses: -(2(2x+3)), so:We get rid of parentheses
2(2x+3)
We multiply parentheses
4x+6
Back to the equation:
-(4x+6)
3x-4x-6+6=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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