2x-3(x+4)=7(x+1)+13

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Solution for 2x-3(x+4)=7(x+1)+13 equation: 



2x-3(x+4)=7(x+1)+13

We move all terms to the left:

2x-3(x+4)-(7(x+1)+13)=0

We multiply parentheses

2x-3x-(7(x+1)+13)-12=0



We calculate terms in parentheses: -(7(x+1)+13), so:

7(x+1)+13

We multiply parentheses

7x+7+13

We add all the numbers together, and all the variables

7x+20

Back to the equation:

-(7x+20)



We add all the numbers together, and all the variables

-1x-(7x+20)-12=0

We get rid of parentheses

-1x-7x-20-12=0

We add all the numbers together, and all the variables

-8x-32=0

We move all terms containing x to the left, all other terms to the right

-8x=32

x=32/-8

x=-4

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