3(x+2)=-5-2(x-3)=(x-1)+7

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Solution for 3(x+2)=-5-2(x-3)=(x-1)+7 equation: 



3(x+2)=-5-2(x-3)=(x-1)+7

We move all terms to the left:

3(x+2)-(-5-2(x-3))=0

We multiply parentheses

3x-(-5-2(x-3))+6=0



We calculate terms in parentheses: -(-5-2(x-3)), so:

-5-2(x-3)

determiningTheFunctionDomain
-2(x-3)-5

We multiply parentheses

-2x+6-5

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We get rid of parentheses

3x+2x-1+6=0

We add all the numbers together, and all the variables

5x+5=0

We move all terms containing x to the left, all other terms to the right

5x=-5

x=-5/5

x=-1

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