1/2(2b-6)+11=8b-13

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Solution for 1/2(2b-6)+11=8b-13 equation: 



1/2(2b-6)+11=8b-13

We move all terms to the left:

1/2(2b-6)+11-(8b-13)=0



Domain of the equation: 2(2b-6)!=0

b∈R



We get rid of parentheses

1/2(2b-6)-8b+13+11=0

We multiply all the terms by the denominator


-8b*2(2b-6)+13*2(2b-6)+11*2(2b-6)+1=0

Wy multiply elements

-16b^2(2+26b(2+22b(2+1=0

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