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3(x+2)=-2(3x+5)-12
We move all terms to the left:
3(x+2)-(-2(3x+5)-12)=0
We multiply parentheses
3x-(-2(3x+5)-12)+6=0
We calculate terms in parentheses: -(-2(3x+5)-12), so:We get rid of parentheses
-2(3x+5)-12
We multiply parentheses
-6x-10-12
We add all the numbers together, and all the variables
-6x-22
Back to the equation:
-(-6x-22)
3x+6x+22+6=0
We add all the numbers together, and all the variables
9x+28=0
We move all terms containing x to the left, all other terms to the right
9x=-28
x=-28/9
x=-3+1/9
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