7+x=1+2(4x-2)

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Solution for 7+x=1+2(4x-2) equation: 



7+x=1+2(4x-2)

We move all terms to the left:

7+x-(1+2(4x-2))=0



We calculate terms in parentheses: -(1+2(4x-2)), so:

1+2(4x-2)

determiningTheFunctionDomain
2(4x-2)+1

We multiply parentheses

8x-4+1

We add all the numbers together, and all the variables

8x-3

Back to the equation:

-(8x-3)



We get rid of parentheses

x-8x+3+7=0

We add all the numbers together, and all the variables

-7x+10=0

We move all terms containing x to the left, all other terms to the right

-7x=-10

x=-10/-7

x=1+3/7

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