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3(x+2)9x=5
We move all terms to the left:
3(x+2)9x-(5)=0
We multiply parentheses
27x^2+54x-5=0
a = 27; b = 54; c = -5;
Δ = b2-4ac
Δ = 542-4·27·(-5)
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-24\sqrt{6}}{2*27}=\frac{-54-24\sqrt{6}}{54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+24\sqrt{6}}{2*27}=\frac{-54+24\sqrt{6}}{54} $
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