(3x+1)=(x+3)=3(x+1)

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Solution for (3x+1)=(x+3)=3(x+1) equation: 



(3x+1)=(x+3)=3(x+1)

We move all terms to the left:

(3x+1)-((x+3))=0

We get rid of parentheses

3x-((x+3))+1=0



We calculate terms in parentheses: -((x+3)), so:

(x+3)

We get rid of parentheses

x+3

Back to the equation:

-(x+3)



We get rid of parentheses

3x-x-3+1=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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