3(x+2)-x=(x-1)+5

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Solution for 3(x+2)-x=(x-1)+5 equation: 



3(x+2)-x=(x-1)+5

We move all terms to the left:

3(x+2)-x-((x-1)+5)=0

We add all the numbers together, and all the variables

-1x+3(x+2)-((x-1)+5)=0

We multiply parentheses

-1x+3x-((x-1)+5)+6=0



We calculate terms in parentheses: -((x-1)+5), so:

(x-1)+5

We get rid of parentheses

x-1+5

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We add all the numbers together, and all the variables

2x-(x+4)+6=0

We get rid of parentheses

2x-x-4+6=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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