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8(x+1)=2(2x+4)
We move all terms to the left:
8(x+1)-(2(2x+4))=0
We multiply parentheses
8x-(2(2x+4))+8=0
We calculate terms in parentheses: -(2(2x+4)), so:We get rid of parentheses
2(2x+4)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
8x-4x-8+8=0
We add all the numbers together, and all the variables
4x=0
x=0/4
x=0
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