3(x+2)-5=6x-3(1+x)

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Solution for 3(x+2)-5=6x-3(1+x) equation: 



3(x+2)-5=6x-3(1+x)

We move all terms to the left:

3(x+2)-5-(6x-3(1+x))=0

We add all the numbers together, and all the variables

3(x+2)-(6x-3(x+1))-5=0

We multiply parentheses

3x-(6x-3(x+1))+6-5=0



We calculate terms in parentheses: -(6x-3(x+1)), so:

6x-3(x+1)

We multiply parentheses

6x-3x-3

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

3x-(3x-3)+1=0

We get rid of parentheses

3x-3x+3+1=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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