1100x+4x2=4464

Solution for 1100x+4x2=4464 equation:

1100x+4x^2=4464

We move all terms to the left:

1100x+4x^2-(4464)=0

a = 4; b = 1100; c = -4464;
Δ = b2-4ac
Δ = 11002-4·4·(-4464)
Δ = 1281424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1281424}=1132$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1100)-1132}{2*4}=\frac{-2232}{8}
=-279
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1100)+1132}{2*4}=\frac{32}{8}
=4
$