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(5/2)x=-3/2
We move all terms to the left:
(5/2)x-(-3/2)=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/2)x-(-3/2)=0
We multiply parentheses
5x^2-(-3/2)=0
We get rid of parentheses
5x^2+3/2=0
We multiply all the terms by the denominator
5x^2*2+3=0
Wy multiply elements
10x^2+3=0
a = 10; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·10·3
Δ = -120
Delta is less than zero, so there is no solution for the equation
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