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2(x-4)+12=2(2x+8)
We move all terms to the left:
2(x-4)+12-(2(2x+8))=0
We multiply parentheses
2x-(2(2x+8))-8+12=0
We calculate terms in parentheses: -(2(2x+8)), so:We add all the numbers together, and all the variables
2(2x+8)
We multiply parentheses
4x+16
Back to the equation:
-(4x+16)
2x-(4x+16)+4=0
We get rid of parentheses
2x-4x-16+4=0
We add all the numbers together, and all the variables
-2x-12=0
We move all terms containing x to the left, all other terms to the right
-2x=12
x=12/-2
x=-6
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