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3(x+2)-5-4x=-5x-3(2x-1)+9x
We move all terms to the left:
3(x+2)-5-4x-(-5x-3(2x-1)+9x)=0
We add all the numbers together, and all the variables
-4x+3(x+2)-(-5x-3(2x-1)+9x)-5=0
We multiply parentheses
-4x+3x-(-5x-3(2x-1)+9x)+6-5=0
We calculate terms in parentheses: -(-5x-3(2x-1)+9x), so:We add all the numbers together, and all the variables
-5x-3(2x-1)+9x
We add all the numbers together, and all the variables
4x-3(2x-1)
We multiply parentheses
4x-6x+3
We add all the numbers together, and all the variables
-2x+3
Back to the equation:
-(-2x+3)
-1x-(-2x+3)+1=0
We get rid of parentheses
-1x+2x-3+1=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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