(1/3)*(2x-1)=2x+13

Solution for (1/3)*(2x-1)=2x+13 equation:

(1/3)(2x-1)=2x+13

We move all terms to the left:

(1/3)(2x-1)-(2x+13)=0


Domain of the equation: 3)(2x-1)!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)(2x-1)-(2x+13)=0

We get rid of parentheses

(+1/3)(2x-1)-2x-13=0

We multiply parentheses ..

(+2x^2+1/3*-1)-2x-13=0

We multiply all the terms by the denominator


(+2x^2+1-2x*3*-1)-13*3*-1)=0

We add all the numbers together, and all the variables

(+2x^2+1-2x*3*-1)=0

We get rid of parentheses

2x^2-2x*3*+1-1=0

We add all the numbers together, and all the variables

2x^2-2x*3*=0

Wy multiply elements

2x^2-6x^2=0

We add all the numbers together, and all the variables

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$