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3(x+2)-2(x-5)=5(x-1)-3(x-6)
We move all terms to the left:
3(x+2)-2(x-5)-(5(x-1)-3(x-6))=0
We multiply parentheses
3x-2x-(5(x-1)-3(x-6))+6+10=0
We calculate terms in parentheses: -(5(x-1)-3(x-6)), so:We add all the numbers together, and all the variables
5(x-1)-3(x-6)
We multiply parentheses
5x-3x-5+18
We add all the numbers together, and all the variables
2x+13
Back to the equation:
-(2x+13)
x-(2x+13)+16=0
We get rid of parentheses
x-2x-13+16=0
We add all the numbers together, and all the variables
-1x+3=0
We move all terms containing x to the left, all other terms to the right
-x=-3
x=-3/-1
x=+3
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