1/2(10x+2)=1/3(9x-27)

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Solution for 1/2(10x+2)=1/3(9x-27) equation: 



1/2(10x+2)=1/3(9x-27)

We move all terms to the left:

1/2(10x+2)-(1/3(9x-27))=0



Domain of the equation: 2(10x+2)!=0

x∈R





Domain of the equation: 3(9x-27))!=0

x∈R



We calculate fractions


(3x9/(2(10x+2)*3(9x-27)))+(-2x1/(2(10x+2)*3(9x-27)))=0



We calculate terms in parentheses: +(3x9/(2(10x+2)*3(9x-27))), so:

3x9/(2(10x+2)*3(9x-27))

We multiply all the terms by the denominator


3x9

We add all the numbers together, and all the variables

3x^9

We do not support expression: x^9

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