(x+12)/(x-3)=9/6

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Solution for (x+12)/(x-3)=9/6 equation: 



(x+12)/(x-3)=9/6

We move all terms to the left:

(x+12)/(x-3)-(9/6)=0



Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R



We add all the numbers together, and all the variables

(x+12)/(x-3)-(+9/6)=0

We get rid of parentheses

(x+12)/(x-3)-9/6=0

We calculate fractions


(6x+72)/(6x-18)+(-9x+27)/(6x-18)=0

We multiply all the terms by the denominator


(6x+72)+(-9x+27)=0

We get rid of parentheses

6x-9x+72+27=0

We add all the numbers together, and all the variables

-3x+99=0

We move all terms containing x to the left, all other terms to the right

-3x=-99

x=-99/-3

x=+33

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