3(x+2)-18=2(3x+5)

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Solution for 3(x+2)-18=2(3x+5) equation: 



3(x+2)-18=2(3x+5)

We move all terms to the left:

3(x+2)-18-(2(3x+5))=0

We multiply parentheses

3x-(2(3x+5))+6-18=0



We calculate terms in parentheses: -(2(3x+5)), so:

2(3x+5)

We multiply parentheses

6x+10

Back to the equation:

-(6x+10)



We add all the numbers together, and all the variables

3x-(6x+10)-12=0

We get rid of parentheses

3x-6x-10-12=0

We add all the numbers together, and all the variables

-3x-22=0

We move all terms containing x to the left, all other terms to the right

-3x=22

x=22/-3

x=-7+1/3

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