10+2(x-4)=3(-7-x)=6

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Solution for 10+2(x-4)=3(-7-x)=6 equation: 



10+2(x-4)=3(-7-x)=6

We move all terms to the left:

10+2(x-4)-(3(-7-x))=0

We add all the numbers together, and all the variables

2(x-4)-(3(-1x-7))+10=0

We multiply parentheses

2x-(3(-1x-7))-8+10=0



We calculate terms in parentheses: -(3(-1x-7)), so:

3(-1x-7)

We multiply parentheses

-3x-21

Back to the equation:

-(-3x-21)



We add all the numbers together, and all the variables

2x-(-3x-21)+2=0

We get rid of parentheses

2x+3x+21+2=0

We add all the numbers together, and all the variables

5x+23=0

We move all terms containing x to the left, all other terms to the right

5x=-23

x=-23/5

x=-4+3/5

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