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3(x+2)+7=1+9(x+9)-7
We move all terms to the left:
3(x+2)+7-(1+9(x+9)-7)=0
We multiply parentheses
3x-(1+9(x+9)-7)+6+7=0
We calculate terms in parentheses: -(1+9(x+9)-7), so:We add all the numbers together, and all the variables
1+9(x+9)-7
determiningTheFunctionDomain 9(x+9)+1-7
We add all the numbers together, and all the variables
9(x+9)-6
We multiply parentheses
9x+81-6
We add all the numbers together, and all the variables
9x+75
Back to the equation:
-(9x+75)
3x-(9x+75)+13=0
We get rid of parentheses
3x-9x-75+13=0
We add all the numbers together, and all the variables
-6x-62=0
We move all terms containing x to the left, all other terms to the right
-6x=62
x=62/-6
x=-10+1/3
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