4y+4-2(-5y-3)=2(y-4)

Solution for 4y+4-2(-5y-3)=2(y-4) equation:

4y+4-2(-5y-3)=2(y-4)

We move all terms to the left:

4y+4-2(-5y-3)-(2(y-4))=0

We multiply parentheses

4y+10y-(2(y-4))+6+4=0


We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)


We add all the numbers together, and all the variables

14y-(2y-8)+10=0

We get rid of parentheses

14y-2y+8+10=0

We add all the numbers together, and all the variables

12y+18=0

We move all terms containing y to the left, all other terms to the right

12y=-18

y=-18/12

y=-1+1/2