3(x+2)+4x-5=7(x+1)-1

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Solution for 3(x+2)+4x-5=7(x+1)-1 equation:



3(x+2)+4x-5=7(x+1)-1
We move all terms to the left:
3(x+2)+4x-5-(7(x+1)-1)=0
We add all the numbers together, and all the variables
4x+3(x+2)-(7(x+1)-1)-5=0
We multiply parentheses
4x+3x-(7(x+1)-1)+6-5=0
We calculate terms in parentheses: -(7(x+1)-1), so:
7(x+1)-1
We multiply parentheses
7x+7-1
We add all the numbers together, and all the variables
7x+6
Back to the equation:
-(7x+6)
We add all the numbers together, and all the variables
7x-(7x+6)+1=0
We get rid of parentheses
7x-7x-6+1=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation

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