3(x+2)+4=4(x-1)+20

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Solution for 3(x+2)+4=4(x-1)+20 equation: 



3(x+2)+4=4(x-1)+20

We move all terms to the left:

3(x+2)+4-(4(x-1)+20)=0

We multiply parentheses

3x-(4(x-1)+20)+6+4=0



We calculate terms in parentheses: -(4(x-1)+20), so:

4(x-1)+20

We multiply parentheses

4x-4+20

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

3x-(4x+16)+10=0

We get rid of parentheses

3x-4x-16+10=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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