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3(x+2)+4(2x+1)=6+20
We move all terms to the left:
3(x+2)+4(2x+1)-(6+20)=0
We add all the numbers together, and all the variables
3(x+2)+4(2x+1)-26=0
We multiply parentheses
3x+8x+6+4-26=0
We add all the numbers together, and all the variables
11x-16=0
We move all terms containing x to the left, all other terms to the right
11x=16
x=16/11
x=1+5/11
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