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3(x+2)+1=6x-3(-4+x)
We move all terms to the left:
3(x+2)+1-(6x-3(-4+x))=0
We add all the numbers together, and all the variables
3(x+2)-(6x-3(x-4))+1=0
We multiply parentheses
3x-(6x-3(x-4))+6+1=0
We calculate terms in parentheses: -(6x-3(x-4)), so:We add all the numbers together, and all the variables
6x-3(x-4)
We multiply parentheses
6x-3x+12
We add all the numbers together, and all the variables
3x+12
Back to the equation:
-(3x+12)
3x-(3x+12)+7=0
We get rid of parentheses
3x-3x-12+7=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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