(m-11)(5m-2)=0

Solution for (m-11)(5m-2)=0 equation:

(m-11)(5m-2)=0

We multiply parentheses ..

(+5m^2-2m-55m+22)=0

We get rid of parentheses

5m^2-2m-55m+22=0

We add all the numbers together, and all the variables

5m^2-57m+22=0

a = 5; b = -57; c = +22;
Δ = b2-4ac
Δ = -572-4·5·22
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-53}{2*5}=\frac{4}{10}
=2/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+53}{2*5}=\frac{110}{10}
=11
$