3(x+2)+-3(6-2x)=16

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Solution for 3(x+2)+-3(6-2x)=16 equation: 



3(x+2)+-3(6-2x)=16

We move all terms to the left:

3(x+2)+-3(6-2x)-(16)=0

determiningTheFunctionDomain
3(x+2)-3(6-2x)-16+=0

We add all the numbers together, and all the variables

3(x+2)-3(-2x+6)-16+=0

We add all the numbers together, and all the variables

3(x+2)-3(-2x+6)=0

We multiply parentheses

3x+6x+6-18=0

We add all the numbers together, and all the variables

9x-12=0

We move all terms containing x to the left, all other terms to the right

9x=12

x=12/9

x=1+1/3

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