3(x+2)+(x-4)=x-3(x+3)

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Solution for 3(x+2)+(x-4)=x-3(x+3) equation: 



3(x+2)+(x-4)=x-3(x+3)

We move all terms to the left:

3(x+2)+(x-4)-(x-3(x+3))=0

We multiply parentheses

3x+(x-4)-(x-3(x+3))+6=0

We get rid of parentheses

3x+x-(x-3(x+3))-4+6=0



We calculate terms in parentheses: -(x-3(x+3)), so:

x-3(x+3)

We multiply parentheses

x-3x-9

We add all the numbers together, and all the variables

-2x-9

Back to the equation:

-(-2x-9)



We add all the numbers together, and all the variables

4x-(-2x-9)+2=0

We get rid of parentheses

4x+2x+9+2=0

We add all the numbers together, and all the variables

6x+11=0

We move all terms containing x to the left, all other terms to the right

6x=-11

x=-11/6

x=-1+5/6

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