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(G)=1/4G+6
We move all terms to the left:
(G)-(1/4G+6)=0
Domain of the equation: 4G+6)!=0We get rid of parentheses
G∈R
G-1/4G-6=0
We multiply all the terms by the denominator
G*4G-6*4G-1=0
Wy multiply elements
4G^2-24G-1=0
a = 4; b = -24; c = -1;
Δ = b2-4ac
Δ = -242-4·4·(-1)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{37}}{2*4}=\frac{24-4\sqrt{37}}{8} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{37}}{2*4}=\frac{24+4\sqrt{37}}{8} $
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