3(x+12)+1=x+2(4+x)

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Solution for 3(x+12)+1=x+2(4+x) equation: 



3(x+12)+1=x+2(4+x)

We move all terms to the left:

3(x+12)+1-(x+2(4+x))=0

We add all the numbers together, and all the variables

3(x+12)-(x+2(x+4))+1=0

We multiply parentheses

3x-(x+2(x+4))+36+1=0



We calculate terms in parentheses: -(x+2(x+4)), so:

x+2(x+4)

We multiply parentheses

x+2x+8

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

3x-(3x+8)+37=0

We get rid of parentheses

3x-3x-8+37=0

We add all the numbers together, and all the variables

29!=0

There is no solution for this equation

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