4(51-50)+40=n

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Solution for 4(51-50)+40=n equation: 



4(51-50)+40=n

We move all terms to the left:

4(51-50)+40-(n)=0

We add all the numbers together, and all the variables

-n+40+41=0

We add all the numbers together, and all the variables

-1n+81=0

We move all terms containing n to the left, all other terms to the right

-n=-81

n=-81/-1

n=+81

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