3(x+1)=21+3x/2

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Solution for 3(x+1)=21+3x/2 equation: 



3(x+1)=21+3x/2

We move all terms to the left:

3(x+1)-(21+3x/2)=0

We add all the numbers together, and all the variables

3(x+1)-(3x/2+21)=0

We multiply parentheses

3x-(3x/2+21)+3=0

We get rid of parentheses

3x-3x/2-21+3=0

We multiply all the terms by the denominator


3x*2-3x-21*2+3*2=0

We add all the numbers together, and all the variables

-3x+3x*2-36=0

Wy multiply elements

-3x+6x-36=0

We add all the numbers together, and all the variables

3x-36=0

We move all terms containing x to the left, all other terms to the right

3x=36

x=36/3

x=12

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