3(x+1)=2(x-3)+x

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Solution for 3(x+1)=2(x-3)+x equation: 



3(x+1)=2(x-3)+x

We move all terms to the left:

3(x+1)-(2(x-3)+x)=0

We multiply parentheses

3x-(2(x-3)+x)+3=0



We calculate terms in parentheses: -(2(x-3)+x), so:

2(x-3)+x

We add all the numbers together, and all the variables

x+2(x-3)

We multiply parentheses

x+2x-6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

3x-3x+6+3=0

We add all the numbers together, and all the variables

9!=0

There is no solution for this equation

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