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3x-1/3x=14
We move all terms to the left:
3x-1/3x-(14)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
3x*3x-14*3x-1=0
Wy multiply elements
9x^2-42x-1=0
a = 9; b = -42; c = -1;
Δ = b2-4ac
Δ = -422-4·9·(-1)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-30\sqrt{2}}{2*9}=\frac{42-30\sqrt{2}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+30\sqrt{2}}{2*9}=\frac{42+30\sqrt{2}}{18} $
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