3(x+1)-2x=x-(2+3)(3-2x)

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Solution for 3(x+1)-2x=x-(2+3)(3-2x) equation: 



3(x+1)-2x=x-(2+3)(3-2x)

We move all terms to the left:

3(x+1)-2x-(x-(2+3)(3-2x))=0

We add all the numbers together, and all the variables

3(x+1)-2x-(x-5(-2x+3))=0

We add all the numbers together, and all the variables

-2x+3(x+1)-(x-5(-2x+3))=0

We multiply parentheses

-2x+3x-(x-5(-2x+3))+3=0



We calculate terms in parentheses: -(x-5(-2x+3)), so:

x-5(-2x+3)

We multiply parentheses

x+10x-15

We add all the numbers together, and all the variables

11x-15

Back to the equation:

-(11x-15)



We add all the numbers together, and all the variables

x-(11x-15)+3=0

We get rid of parentheses

x-11x+15+3=0

We add all the numbers together, and all the variables

-10x+18=0

We move all terms containing x to the left, all other terms to the right

-10x=-18

x=-18/-10

x=1+4/5

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