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1/3(y+3)=2y
We move all terms to the left:
1/3(y+3)-(2y)=0
Domain of the equation: 3(y+3)!=0We add all the numbers together, and all the variables
y∈R
-2y+1/3(y+3)=0
We multiply all the terms by the denominator
-2y*3(y+3)+1=0
Wy multiply elements
-6y^2(y+1=0
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