3(x+1)-2(x-4)=2(x-1)

Solution for 3(x+1)-2(x-4)=2(x-1) equation:

3(x+1)-2(x-4)=2(x-1)

We move all terms to the left:

3(x+1)-2(x-4)-(2(x-1))=0

We multiply parentheses

3x-2x-(2(x-1))+3+8=0


We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)


We add all the numbers together, and all the variables

x-(2x-2)+11=0

We get rid of parentheses

x-2x+2+11=0

We add all the numbers together, and all the variables

-1x+13=0

We move all terms containing x to the left, all other terms to the right

-x=-13

x=-13/-1

x=+13