(x+4-10)(x+4-10)=0

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Solution for (x+4-10)(x+4-10)=0 equation: 



(x+4-10)(x+4-10)=0

We add all the numbers together, and all the variables

(x-6)(x-6)=0

We multiply parentheses ..

(+x^2-6x-6x+36)=0

We get rid of parentheses

x^2-6x-6x+36=0

We add all the numbers together, and all the variables

x^2-12x+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{2}=6$

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