3(x+1)+2=5+2(x+1)

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Solution for 3(x+1)+2=5+2(x+1) equation: 



3(x+1)+2=5+2(x+1)

We move all terms to the left:

3(x+1)+2-(5+2(x+1))=0

We multiply parentheses

3x-(5+2(x+1))+3+2=0



We calculate terms in parentheses: -(5+2(x+1)), so:

5+2(x+1)

determiningTheFunctionDomain
2(x+1)+5

We multiply parentheses

2x+2+5

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We add all the numbers together, and all the variables

3x-(2x+7)+5=0

We get rid of parentheses

3x-2x-7+5=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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