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(6x+6)x=14
We move all terms to the left:
(6x+6)x-(14)=0
We multiply parentheses
6x^2+6x-14=0
a = 6; b = 6; c = -14;
Δ = b2-4ac
Δ = 62-4·6·(-14)
Δ = 372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{372}=\sqrt{4*93}=\sqrt{4}*\sqrt{93}=2\sqrt{93}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{93}}{2*6}=\frac{-6-2\sqrt{93}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{93}}{2*6}=\frac{-6+2\sqrt{93}}{12} $
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